Laws of Mechanics
- Newton’s
laws of motion
- Newton’s
law of gravitation
- The parallelogram
law
- Principle
of transmissibility of force
Newton’s laws of motion
First Law: -
A body
remains at rest or continues to move with uniform velocity (in a straight line
with a constant speed) if there is no external force acting on it.
Example
If a ball
is rolling on a plane surface (neglecting the effect of air resistance,
friction resistance etc.), if we want to stop or reduce the speed of ball, we
have to applied some resistance against the motion of the ball to stop or
reduce the speed of the ball.
Q A bus
running at a speed of 60 km/hr on a straight road. Air resistance and friction
force between tyre and road surface are experience by a bus during running. What
amount of force driver is to apply on accelerator pedal to maintain the speed
of bus at 60 km/hr?
(A)Equal to Air resistance (B)Equal to Friction force
(C)Sum of Air resistance and friction force (D) Can’t say
Q A block having
mass m is rest on a rough surface, the coefficient of friction between the
surface and block is u. what amount of force is to be applied on block to move
it over the rough surface.
Give the answer in comment box
Second Law: -
The rate
of change in linear momentum of a body is proportional to the impressed force
and takes place in the direction of the applied force.
The product
of mass (m) and velocity (v) is called momentum.
F = Applied
force (units) m = mass
of body (units) v =
linear velocity (units)
We very
well know that mass of the body is constant but velocity depends on distance
and time.
Rate of change
of velocity = final velocity – initial velocity
Final velocity
(v2) = velocity of a particle after t interval of time
Initial
velocity (v1) = velocity of particle at t becomes zero.
The rate
of change of linear momentum =
mass * (final velocity – initial velocity)
=
m*(v2 – v1) units
And
The applied
force F = m*(v2 – v1) = m*a (units) [a=
linear Acceleration]
The above equation
use
To find
force needed to brake the momentum
To find
acceleration of a body etc.
Third Law:-
To every
action, there is an equal and opposite reaction.
The force
of action and reaction between interacting bodies are equal in magnitude,
opposite in direction, and collinear.
Question
Give the real life examples of Second law and third law in comment.
F= GMm/r2 G= 6.67*10^-11 m^2 /kg s^2
g = GM/r2 =
gravitational constant
Figure - Gravitational law of force
Figure - Principle of Transmissibility of forces
Newton’s law of gravitation
Two
particles are mutual attracted along their connecting line with a force whose
magnitude is directly proportional to the product of their masses and inversely
proportional to the square of the distance between them.
Body 1 having mass m
|
F =
gm
g =
[(6.67*10^-11)* (5.972*10^24)]/ 6371000 = 9.81 unit
Principle of Transmissibility of force
The point
of application of a force applied to a rigid body may be transmitted anywhere
along its line of action without changing its resultant effects external to the
rigid body.
Figure - Principle of Transmissibility of forces